We need some clarification as to the operation of the FUSE pin. Looking at the simple FUSE drive circuit shown in Figure 2 of the data sheet (see below), there are a couple of questions:
- When is the 150 nA pull-up current applied and does this remain on during normal operation of the gauge?
- When the FUSEEN switch is open (i.e.gauge not driving FUSE output high), I assume the FUSE pin is not being actively driven low by the gauge, correct?.
- But if the 150 nA current source is on, then the circuit must be relying on external resistance to ground to keep the voltage from floating high enough to trip the FUSEDIG comparator. Is this understanding correct?
