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LM66100: optimizing current consumption

Bart
Expert 6460 points
Part Number: LM66100

We have a circuit with 2x LM66100. The current trough inactive IC is 22uA @R3=100k – because of R3. This is to much for our application.

  • How can this current be completely cancelled?

Supply is made by 2x 2 batteries in series.

Thanks for help.

  • 0
    TI__Mastermind 32650 points

    Hey Bart,

    I assume you mean you are seeing 22uA through R3 when D1 is off.

    In this situation, ST is an open drain that is pulled to GND so there will be some sink of current from the rail, through this resistor and into the ST pin.

    It is possible to further increase this R3 resistance? Also I don't immediately see why you have resistors R1 and R2? I don't think they are hurting anything but you could remove them.

    It is possible to diode OR without using the ST pin, but since your sources are quite similar in voltage you may run into the situation described in Section 9.2.2 (continuous output power) in the datasheet.