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BQ24610: BQ24610 the charging light is on, but the current is 0

Part Number: BQ24610

Hi

Recently, we are using BQ24610 for 6 series of lithium batteries, full charge voltage is 25.2V and input voltage is 28V.

When connected to 28V voltage, PG lamp is always on. When not connected to battery, the voltage at each point is: VIN=28V;VTTC = 1.24 V.VTS = 1.48 V.VPH = 27.24 V.VREF = 3.29 V.VREGN = 5.96 V.VISET1 = 0.3 V.VISET2 = 0.3 V.VACSET = 0.4 V.VFB = 2.26 V.

The battery voltage is 24.3v. When the battery is connected, the charging lamp will be on. The voltage at each point is VIN=28V.VTTC = 1.0 V.VTS = 1.48 V.VPH = 24.3 V.VREF = 3.29 V.VREGN = 5.96 V.VISET1 = 0.3 V.VISET2 = 0.3 V.VACSET = 0.4 V.VFB = 2.018 V. The total current of VIN is only 40mA

When the battery is plugged in and the charging light is on for less than 2 minutes or less, it will automatically turn off. At this point, I touch the BQ24610 chip and the temperature is very high. After that, only PG light is always on.

PS: JE06 is not used. Its positive pole has been connected to the positive pole of JE07

PH waveform

LODRV waveform

Waiting for your reply

Thanks

Star

  • Hey Star,

    The first thing I will note is that you have a DGND connected to the IC. This is not correct. The charger GND pin should be connected to your power ground, as it will be processing power for the gate drivers. 

    Second, I see several traces they have thermal relief type connections, but this is likely creating more impedance and may be contributing to higher power loss.

    I do not have any insight into your MOSFETs or your inductor, but I would compare those against the EVM components in terms of DCR, Coss, Ciss, Rdson to get a better idea of the potential increase in power loss.

    From your layout picture, I cannot tell what your ground layer looks like. Do have an image of the second layer?

    Regards,

    Joel H

  • Hey Star,

    Any update on this? If you have resolved your issue, we will close this thread.

    Regards,

    Joel H