Hi,
Could you please tell me the voltage of "Vpull-up" and the value of the pull-up resistor regarding the /QON circuit?
Best regards,
Kato
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Hi,
Could you please tell me the voltage of "Vpull-up" and the value of the pull-up resistor regarding the /QON circuit?
Best regards,
Kato
Hey Sadanori,
The voltage is a derivative of the battery voltage or the input voltage. It is the higher of VBUS - 1.4V or VBAT - 0.7V. And the pullup resistance is ~200kOhm.
Regards,
Joel H
Hi Joel-san,
Thank you for your prompt reply.
I would like to confirm just in case but it seems that the absolute maximum rating of the /QON terminal may be exceeded when 13.5V is applied to the VBUS terminal and "VBUS - 1.4V" is selected as the Vpull-up voltage.
Additionally, how does the BQ25601D switch between "VBUS - 1.4V " and "VBAT - 0.7V" during operating ?
Best regards,
Kato
Hey Kato,
This is an internal pullup. The pin cannot handle external voltages above 7V.
And the switch between VBUS or VBAT is proprietary information. We cannot provide this.
Regards,
Joel H
Hi Joel-san,
Thank you for the information.
I understand that the architecture to switch between VBUS and VBAT cannot be disclosed.
Is my understanding correct that the terminal voltage for /QON doesn't exceed AbsMax 7V if VBUS is selected at 13.5V and /QON is kept floating?
Best regards,
Kato
Hey Kato,
So I just tested this on my bench and I will have to rescind my previous statement and discuss internally.
On the bench, the /QON pullup is definitely a function of either VBUS or VBAT, but there some clamping element internally. I will get back to you.
Regards,
Joel H
Hey Kato,
I will have to rescind my previous comments.
The pull-up voltage on /QON has two diode drops from VBUS or one diode drop from VBAT. The forward voltage of these diodes can be higher than 0.7V each.
Additionally, there is a 6V clamp on this rail, which means /QON will never be puled up beyond 6V.
Regards,
Joel H
Hi Joel-san,
Thank you for the detailed information.
I understand.
Best regards,
Kato