Dear *,
we are designing the schematic for LM5176 and have some questions.
Our input voltage for normal operation is from 12V to 24V.
1) What is the minimal voltage that needs to be applied to Vin (pin28 QFN) to get the VCC=7.35V?
Vin = Vcc + Vs + Vinternal
Vs -> voltage drop on series blocking diode
Vinternal -> voltage drop on internal linear regulator
We are not using BIAS pin connected to Vout, nor we are supplying BIAS voltage -> BIAS is NC(not connected)
2) Does it make sense to connect the BIAS pin to VIN pin?
3) If we don't use BIAS pin and UVLO is set to 9V do we then need the series blocking diode?
4) In the DS on page 23 under typical application 8.2.2.9 the EN/UVLO hysteresis is selected to be 0.8V , why is this so? Why didn't you select 0.4V (lower) or 1.6V(grater)?
5) Of we want that the LM5176 turns off when Vin=10V or below, and the hysteresis is 0.8V then the turn on voltage is UVLO+Vhys
=10V +0.8V is that correct?
6) if we use additional Rs(series resistor to EN/UVLO pin like this https://e2e.ti.com/support/power-management/f/196/p/680351/2506288?tisearch=e2e-sitesearch&keymatch=lm5176%2520uvlo%2520hysteresis#2506288)
how is then the UVLO and Vhys calculated?
Best Regards,
David.