BQ24170: BQ24170 - 15 μA Battery current with adapter removed

Hello, 

Do you have any load on VSYS?

If you remove Q5, does the current reduce?

Regards,

Joel H

Dear Ondrej,

The 15 uA leakage is measured on a tester with no active components connected to the IC. As such, I would look at the active component leakage currents in your circuits, such as diode reverse current.

I would also recommend checking the ACDRV voltage. If it is not close to 0 V, you may need a 500 kOhm resistor from ACDRV to CSMRC to drain the charge pump. This is recommended in the datasheet.

Thanks,

Mike Emanuel

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Hello,

thank you so much for your replay.

1. No, I don't have any load on VSYS (Q3 is removed too)
2. If I remove Q5 the current is still the same
3. I know that each active components consumes some (leakage) current, but more than 100 uA is too much for my circuit. I need total current less then 30 uA
4. I added 500 kOhm resistor from ACDRV to CSMRC - now voltage on ACDRV to CSMRC is 1.8mV

For measure I use UT61E multimeter
PCB is clear from a flux and a impurities
Every components are as close as possible
Could someone please measure this circuit? ..or the bq24170EVM Evaluation Module

Thank you for your advice,
Ondrej

Dear Ondrej,

I measured on the EVM and concluded that the battery discharge current into the IC was less than 13 uA. I think there is another leakage path somewhere.

Thanks,

Mike Emanuel

Please click "This resolved my issue" button if this post answers your question.