Hi,
If the load is short-circuited (due to mis-wiring or water drops or dust adhering to the load side during operation) and the load impedance during short-circuit assumes about 0.2Ω,
(1) Calculate simply, the short-circuit current is 12V / 0.2Ω = 60A. With the current limit of 4.5A, wouldn't it overshoot to 4.5A or more? If so, how much will you overshoot?
(2) Even if overshoot occurs, can it be kept within the range where the regulator is NO damage?
(3) How long does it take from the detection of a current of 4.5A or more to the restriction?
(4) When the current limit is working (limited to 4.5A), will the output voltage drop? Will it maintain 12V?
(5) If the short-circuit current shifts from 4.5A or more to about 2A by another protection circuit, will the current limit function be released and return to normal operation?
The following condition is as follows:
Device : LM2673T-ADJ
Input : DC20-30V
Output : About 12V (R1=1kΩ、R2=9.1kΩ)
Current Limit : About 4.5A(Radj=8.2kΩ)
Thanks and best regards,
M.HATTORI.