Other Parts Discussed in Thread: LM5050-2, LM74700-Q1, SM74611
Hi all,
I'm considering using a LM74610 in my application in order to emulate an ideal diode. In my case the connected MOSFET should be turned off as soon as the current reverses (flows from drain to source), or even slightly before that since the body diode can handle small currents.
The datasheet shows however that this only happens once the Anode voltage is 20mV below the Cathode voltage. With a typical Rdson of the used MOSFET of say 2 mohms, that would imply that the device would have to conduct at least 10A in the reverse direction before the emulated diode stops conducting.
I realize that in case the reverse current is too small to hit the -20mV threshold, the chargepump would eventually not be able to sustain the required gate voltage and therefor the device will be switched off anyway.
But this seems to be a bit of an uncontrolled mechanism because the time it takes depends on how fast the gate charge leaks away which is typically not very well controlled.
Is my analysis correct or am I overlooking something? If correct, is there a workaround to make the MOSFET turn off before or at the point where the current reverses?
Best regards,
Paul Beijer
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