BQ25883: bq25883 always enter windpm regulation

It is hard to diagnose the problem without a schematic and without a waveform. However, if you read the register table, it indicates you are in VINDPM regulation because bit 5 of 0x0B is 1. The default setting is 4.3 V. Your adapter may be unable to provide the rated current. This means the voltage on VBUS is dipping below the VINDPM setting and the current is being limited to prevent further dropping of VBUS.

Thanks,

Mike Emanuel

Please click "This resolved my issue" button if this post answers your question.

hi michael,thanks for your reply.

the schematic is designed ref the demo.

1st: the adpater can provide the rated current.(Simulate adapter with DC power supply)

2nd: if set the vindpm 5v      reg 0B value:0X23  indicates enter VINDPM regulation

        if set the vindpm 4.3v   reg 01  value:0x94  indicates enter HIZ

the reg value as showed below:

bq25883 reg:0x00 value:0xA0 
bq25883 reg:0x01 value:0x14 
bq25883 reg:0x02 value:0x8D 
bq25883 reg:0x03 value:0x39 
bq25883 reg:0x04 value:0x22 
bq25883 reg:0x05 value:0xA7 
bq25883 reg:0x06 value:0x3D 
bq25883 reg:0x07 value:0x02 
bq25883 reg:0x08 value:0x0D 
bq25883 reg:0x09 value:0xF6 
bq25883 reg:0x0A value:0x19 
bq25883 reg:0x0B value:0x23 
bq25883 reg:0x0C value:0x80 
bq25883 reg:0x0D value:0x00 
bq25883 reg:0x0E value:0x00 
bq25883 reg:0x0F value:0xE9 
bq25883 reg:0x10 value:0x93 
bq25883 reg:0x11 value:0x08 
bq25883 reg:0x12 value:0x00 
bq25883 reg:0x13 value:0x00 
bq25883 reg:0x14 value:0x00 
bq25883 reg:0x15 value:0xC0 
bq25883 reg:0x16 value:0x02 
bq25883 reg:0x17 value:0x03 
bq25883 reg:0x18 value:0x44 
bq25883 reg:0x19 value:0x01 
bq25883 reg:0x1A value:0xE9 
bq25883 reg:0x1B value:0x14 
bq25883 reg:0x1C value:0x31 
bq25883 reg:0x1D value:0x1F 
bq25883 reg:0x1E value:0x5F 
bq25883 reg:0x1F value:0x1F 
bq25883 reg:0x20 value:0x73 
bq25883 reg:0x21 value:0x02 
bq25883 reg:0x22 value:0x11 
bq25883 reg:0x23 value:0x00 
bq25883 reg:0x24 value:0x44 
bq25883 reg:0x25 value:0x19 

The adapter voltage is 5V

When VINDPM is set to 5V, it can be charged, but into VINDPM REGULATION

When VINDPM is set to 4.3v, go directly to HIZ

In order to further diagnose this problem, I would appreciate if you could provide the schematic you are using. In addition, I would like a waveform of IBUS, VBUS, SW, and IBAT. I would like you to trigger on the edge that VBUS goes high for each setting of VINDPM. The part appears to still be in VINDPM from the registers you provided.

Thanks,

Mike Emanuel

THE SCH IS SHOWN AS ABOVE:

THE BQ25883 is used only as a battery charger.

If you could provide some waveforms (IBUS, VBUS, SW, and IBAT upon startup) for each case of VINPDM that would be helpful. Upon second look at your register settings, 0x80 in REG 0C indicates Power Good with no input. For some reason your input is not being detected.

How long is your input cable (more specifically what is its impedance)? To me, if VINDPM is 5 V, which is your adapter rated voltage, it can pull some of your desired current, but maybe not all because of the impedance of the cable. When you try to pull the desired current at VINDPM of 4.3 V, you may be crashing the adapter.

Thanks,

Mike Emanuel

Please click "This resolved my issue" button if this post answers your question.

thank you for your replly.

In my opinion:

use the same adapter ,different vindpm setting 

Q1:

setting :5V is easier to enter the vindpm regulation(or hiz) than setting 4.3v.

Q2:

I don't understand why bq25883 enter to hiz when the  vindpm value  is setted 4.3v. 

later i will attach the test pic.