Hi,
I calculated equation (48) and the result is 69.59kΩ.
5.3kHz*π*4mΩ*50.725kΩ*10*1030uF*24V/12V=69.59kΩ
Is the following 68.5kΩ correct? or is my using parameter wrong?
Best Regards,
Kuramochi
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Hi,
I calculated equation (48) and the result is 69.59kΩ.
5.3kHz*π*4mΩ*50.725kΩ*10*1030uF*24V/12V=69.59kΩ
Is the following 68.5kΩ correct? or is my using parameter wrong?
Best Regards,
Kuramochi
Hi Kuramochi-san,
I believe it uses 49.9kOhm as the fb resistor instead of the 50.725kOhm. But yours calculation is more accurate.
Thanks,
Yinsong