Hi support team,
I have a question about the following sentence in the TPS61099 data-sheet.
9.2.1.1.2 Programming the Output Voltage, Page-16, SLVSD88K
"For the best accuracy, the current following through R2 should be 100 times larger than FB pin leakage current."
IFB_LKG is 10nA for TYP and 50nA for MAX.
Should the R2 current be above the MAX standard of 5uA?
Or is it okay to have a TYP standard of 1uA or higher?
I want to know the maximum value of R2.
R2 < VREF/(IFB_LKG*100) = 1V/5uA = 200kΩ ?
R2 < VREF/(IFB_LKG*100) = 1V/1uA = 1MΩ ?
Regards,
Dice-K