LM5180: shared total output power

Team, 

Can you help answer my customer's questions below:

We want to use the LM5180 in a nearly identical fashion as shown on page 30 in the datasheet.  Same parts as well.  The design below claims 100mA for 24V and 300mA for 5V.  Our design needs 180mA minimum output current on each rail.  If I’m using less current on the 5V output, does that mean I will have more available on the 24V output (shared total output power?)?  FWIW, the Quickstart Calculator spreadsheet doesn’t show any errors with my 180mA configuration for each rail, which implies it is ok.

However, the datasheet also lists equation #13 for calculating Iout(max), the current limit for invoking “overcurrent mode”.  Perhaps I’m using wrong values, but I calculate a max output current of approximately 280mA for 24V output, and 167mA for 5V.  The latter number concerns me since it’s below our 180mA requirement.

 Can someone tell me if our configuration will work per our 180mA needs?  If not, what changes would we need to make?  Thanks!

Thanks

Viktorija