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TPS62147: Benefits vs TPS62150, SS/TR pin function below 0.9V output voltage.

Part Number: TPS62147
Other Parts Discussed in Thread: TPS62150, TPS62148, TPS62135

Hi there

The new part TPS62147 / TPS62148 seem to be a eventual replacement for the TPS62150. 

I have compiled the table below to illustrate some of these benefits. What I'm surprised about is that it is not always more efficient than it predecessor, despite having Automatic Efficiency Enhancement.

Secondly, the short circuit behaviour of the newer part will likely be a problem. I intend to charge a large capacitance, controlling the output voltage via SS/TR pin using an external DAC, allowing control of the load. With the ESR of the capacitance being 200mR means that it will normally exceed the current limit of both parts. My assumptions are as follows:

  • Minimum Vout is 0.9V (TPS62150) or 0.8V (TPS62147), ideally SS/TR allows this to be reduced further so that the output voltage is low enough not to exceed the current limit.

  • If the above is true, great. If it is not true, then the over current condition will be reached.

  • TPS62147 would hiccup for 512 cycles and wait for 800uS before retrying. This would take a long time making it unsuitable.
  • TPS62148 would behave correctly, provided the supply was not below UVLO. If it did go below the UVLO then the output discharge would kick in and the large capacitance would be drained (not desired). 
  • TPS62150 would current limit, until the load is reduced below the current limit (the capacitor is charged).

  • Under these conditions, it may be that briefly the overcurrent condition is hit anyway - again, hiccuping is not ideal. This means that the TPS62150 is the only choice that will meet the requirements.

My questions:

  1. Confirmation that the TPS62147 isn't as efficient as the TPS62150 all the time, broadly in line with the figures from the table below?
  2. Can the SS/TR pin be used to modify the output voltage below 0.9V / 0.8V respectively? if 0.8V is the minimum (on TPS62147), then across 200mR ESR capacitor the short current will be exceeded.
  3. The TPS62150 does not mind being pre-biased above its target voltage being dictated by SS/TR pin?
  4. Iramp (ramp time) for TPS62147 is 150uS. What is the ramp time for TPS62150?

  TPS62150 TPS62147 / TPS62148
Age November 2011 April 2018
Input range 3 - 17 (20V Ab Max, UVLO 2.8V max falling, 200mV hysteresis) 3 - 17 (20V Ab Max, UVLO 2.7V max falling, 300mV hysteresis)
Output range 0.9 - 6V 0.8 - 12V
Current capability 1A 2A
Output accuracy PWM mode 800 / 814.4 = 1.018 = 1.8% max above, 0.982 = 1.8% min below + / - 1%
Output accuracy PS mode 822.4 / 800 = 1.028 = 2.8% max above, 0.977 = 2.3% min below - 1%, +2%
Other features +5% mode, 100% duty cycle, short protection, soft start 100% duty, short protection, soft start, Automatic efficiency enhancement
Price 1K / availability £0.708 Arrow, £0.566 TI, 154K inventory (findchips) £0.796  mouser, £0.620 TI, 15K inventory
Efficiency at 1.2V out (7V in)   10mA = 83% , 100mA = 85%, 500mA = 86%, 1A = 87%
Efficiency at 1.2V out (12V in)   10mA = 81%, 100mA = 83%, 500mA = 84%, 1A = 85%
Efficiency at 1.2V out (15V in)   10mA = 79%, 100mA = 81%, 500mA = 82%, 1A = 83%
Efficiency at 1.8V out (7V in) 10mA = 85%, 100mA = 86%, 500mA = 89%, 1A = 91% 10mA = 85%, 100mA = 87%, 500mA = 90%, 1A = 90%
Efficiency at 1.8V out (12V in) 10mA = 80%, 100mA = 82%, 500mA = 84%, 1A = 90% 10mA = 84%, 100mA = 86%, 500mA = 87%, 1A = 90%
Efficiency at 1.8V out (15V in) 10mA = 77%, 100mA = 79%, 500mA = 84%, 1A = 88% 10mA = 82%, 100mA = 83%, 500mA = 84%, 1A = 86%
Efficiency at 3.3V out (7V in) 10mA = 91%, 100mA = 92%, 500mA = 93%, 1A = 94% 10mA = 90%, 100mA = 93%, 500mA = 95%, 1A = 95%
Efficiency at 3.3V out (12V in) 10mA = 87%, 100mA = 88%, 500mA = 90%, 1A = 92% 10mA = 88%, 100mA = 88%, 500mA = 89%, 1A = 91%
Efficiency at 3.3V out (15V in) 10mA = 86%, 100mA = 87%, 500mA = 88%, 1A = 90% 10mA = 87%, 100mA = 88%, 500mA = 88%, 1A = 89%
Efficiency at 5V out (7V in) 10mA = 91%, 100mA = 94%, 500mA = 95% , 1A = 96%  10mA = 93%, 100mA = 94%, 500mA = 96%, 1A = 96%
Efficiency at 5V out (12V in) 10mA = 91%, 100mA = 92%, 500mA = 93%, 1A = 95% 10mA = 89%, 100mA = 90%, 500mA = 91%, 1A = 93%
Efficiency at 5V out (15V in) 10mA = 89%, 100mA = 90%, 500mA = 92%, 1A = 94% 10mA = 88%, 100mA = 89%, 500mA = 90%, 1A = 91%
Min SS set / analog in 0.05 to 1.2V full scale, VFB = 0.64 * Vss 0 - 0.7V full scale, VFB = Vss
Short Circuit behaviour?   47 = hiccups 512 cycles / 800uS, 48 = limits current
Other?   48 = has a discharge function when chip is not enabled, OR UVLO condition, OR thermal shutdown
Conclusion Should work 47 hiccup is not suitable neither is discharge function of 48. No good.
  • further to this:
    - These figures are from the datasheet graphs - the 500mA points are a guess by eye, so ignore the 500mA data points.

    - if VFB can be reduced so the output can be below 0.8V / 0.9V, what is the minimum output voltage when SS/TR = 0V on TPS62147 and TPS62150?
  • Hi Charge,

    Yes, the TPS62147/8 is a newer version in this product space, so it should provide mostly advantages over an older device. As you conclude, it may not be better for each and every application as there are differences.

    The TPS62135/6/1 are 4A versions which are pin to pin with TPS62147/8. Of them, the versions ending in 1 (TPS621351/TPS621361) do not have either hiccup or output discharge.

    This post shows the SS time when SS/TR is floating: e2e.ti.com/.../652261

    Yes, each device can deliver an output voltage below its FB pin by driving the SS/TR pin. Here is an example of doing this: www.ti.com/.../slva451a.pdf

    Each device can tolerate the output voltage being pre-biased above its setpoint. Make sure to operate TPS62147/8 in PFM mode so that it doesn't try and sink the output voltage.
  • Thanks, this is what I suspected.

    Your final comment on TPS62148 - if the input to the device is off, then the output would be discharged anyway even if set to PFM mode. With an intermittent power source and a large capacitance on the output this means it would deplete this energy storage each time the input is off (due to UVLO). Is this correct?

    Thanks again for the excellent support.
  • Yes, that device activates its output discharge in UVLO. However, any device will discharge Vout to Vin through the high side FET's body diode as explained here: e2e.ti.com/.../730882

    A diode in series with the output would prevent both.