DM814x GPIO u-boot

Hello Biser
Thanks for reply.
I have provided changes, unfortunately it didn't takes affect...
Source code below:

/board/ti/ti8148/evm.c

#define PADCTRL_BASE 0x48140000

#define PAD161_CNTRL  (*(volatile unsigned int *)(PADCTRL_BASE + 0x0A80))         //GP0[15]
#define PAD163_CNTRL  (*(volatile unsigned int *)(PADCTRL_BASE + 0x0A88))         //GP0[17]
#define PAD168_CNTRL  (*(volatile unsigned int *)(PADCTRL_BASE + 0x0A9C))        //GP0[22]
#define PAD009_CNTRL  (*(volatile unsigned int *)(PADCTRL_BASE + 0x0820))         //GP0[2]

#define CVDD_POWER_MNGR0 ( 1<<15 )        // GP0[15]
#define CVDD_POWER_MNGR1 ( 1<<22 )        // GP0[22]
#define CVDD_POWER_MNGR2 ( 1<<17 )        // GP0[17]
#define CVDD_FORSE_POWER ( 1<<2  )        // GP0[2]

int board_init(void)
{
.....

    // GPIO0 CLK Enable
    __raw_writel(0x2, CM_ALWON_GPIO_0_CLKCTRL);
    while(__raw_readl(CM_ALWON_GPIO_0_CLKCTRL) != 0x2);

.....

    val = PAD161_CNTRL;
    PAD161_CNTRL = (volatile unsigned int)           ( BIT(18) | BIT(16) | BIT(7));    //GP0[15]    
    val = PAD163_CNTRL;
    PAD163_CNTRL = (volatile unsigned int)           ( BIT(18) | BIT(16) | BIT(7));    //GP0[17]
    val = PAD168_CNTRL;
    PAD168_CNTRL = (volatile unsigned int)           ( BIT(18) | BIT(16) | BIT(7));    //GP0[22]
    val = PAD009_CNTRL;
    PAD009_CNTRL = (volatile unsigned int)     ( BIT(19) | BIT(18) | BIT(16) | BIT(7));    //GP0[2]


    // Enable Output on GPIO0
    gpio_reg_val  = __raw_readl(0x48032134);        //0x4803 2134 (GPIO0 Output Enable)
    gpio_reg_val |= ( CVDD_POWER_MNGR0|CVDD_POWER_MNGR1|CVDD_POWER_MNGR2|CVDD_FORSE_POWER );
    __raw_writel(gpio_reg_val, 0x48032134);

    // Clear any existing output data
    gpio_reg_val  = __raw_readl(0x48032190);        //0x4803 2190 (GPIO0 Clear Data Output)
    gpio_reg_val |= ( CVDD_POWER_MNGR0|CVDD_POWER_MNGR1|CVDD_POWER_MNGR2|CVDD_FORSE_POWER );
    __raw_writel(gpio_reg_val, 0x48032190);

    // Set value of GPIO pins
    gpio_reg_val = __raw_readl(0x4803213C);       //0x4803 213C (GPIO0 Data Output)
    gpio_reg_val |= (CVDD_POWER_MNGR0 | CVDD_POWER_MNGR2);
    __raw_writel(gpio_reg_val, 0x4803213C);


    // Program the GPIO to change the voltage
    gpio_reg_val = __raw_readl(0x48032194);        //0x4803 2194 (GPIO0 Set Data Output)
    gpio_reg_val |= (CVDD_POWER_MNGR0 | CVDD_POWER_MNGR2);
    __raw_writel(gpio_reg_val, 0x48032194);   

.....
}

Maybe you have some other suggestions.

Thanks.

Sorry guys,

I have some questions concerning mapping GPIO.

From table 4-13 I saw that GP0[15] has two mapping points:

1. PINCNTL161 (pin AE18) mapping point described as GP0[15](M1)
2. PINCNTL44 (pin H2) mapping point described as GP0[15](M0)


Could you help me to understand how one register (for example 0x4803 213C (GPIO0 Data Output) ) can control two ICs pins.

Could you explain what is M0 and M1, and how I can use it.

Thanks.