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proportion equation between receive power and RCS



Hi. I confuse that the radar equation.

in radar equation, the power equation is same with below

P_r = P_t * G_t * G_r * λ^2 * σ / ((4π)^3 * R^4)

Q.1

Let me guess σ = 1, P_r = 10. If σ = 10, then P_r = 100??

The unit of power is [W].

  • Hi Shuyun,

    Is it possible to rephrase your question differently? I am unable to get a clear understanding of the question you asked.

    If you are asking whether received power is directly proportional to the RCS, then yes. 

    Thanks & regards,

    Kaushik

  • Thank you for answering my question.

    I checked log magnitude of corner reflector in my office.

    Then i converted log to linear scale. After that i converted it db scale.

    i compared rcs:1 and rcs:8 in dB scale. To compare the dB, i subtracted P_rcs:8(dB) to P_rcs:1(dB). The result is 8.1(dB), this means that rcs:8 is 8 times bigger than rcs:1

    If RCS and power directly proportion, my result is right?

  • Hi Shuyun,

    1) Can you explain your conversion from log scale to linear scale and then back to log scale?

    2) RCS is expressed as a unit of area. Can you explain the reasoning behind the dB scale for RCS?

    2) If your observation demonstrates increase in received power with an increase in RCS, it will imply that your observation is right.

    Thanks & Regards,

    Kaushik