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AWR1843BOOST: The range of x and z coordinates visible at each Range detection point

Hiroyuki Kanematu
Expert 2975 points
Part Number: AWR1843BOOST
Other Parts Discussed in Thread: AWR1843

I have two questions below.
(1) Assume that an object in a Range is detected using AWR1843.
At this time, the width of the object in the x-axis direction and the width in the z-axis direction are respectively
Is it okay to think that it can be obtained by 2*R*Wx and 2*R*Wz?
(Wx: Angle of Azimuth, Wz: Angle of Elevation)

If it is different, I would be happy if you could also tell me the derivation process.

(2) When detecting the width of an object with AWR1843
If you want to find the width of each x-z axis direction seen from Radar using AWR1843,
Do you need to look at the difference in the x-axis and z-axis of the object in multiple frames?

  • 0
    TI__Mastermind 20605 points

    Hi Hiroyuki-san,

    Are you correlating the width of the object to the arc length (based on your expression)? 


    Width of the object (along X-Z) can be defined as the distance between farthest points on Z-axis on the X-Z plane. 
    If R is the radial distance, W_az is the azimuth angle & W_el is the elevation angle,
    X = R * sin (W_az) * sin (W_el) 
    Y = R * cos (W_az) * sin (W_el) 
    Z = R * cos (W_el)
    (Please look up 3D co-ordinate system conversion for better understanding here)

    To find the "width" of an object, you would have to find difference between two farthest points on the same axis. (x1,Y,Z) - (x2, Y, Z) [Horizontal] & (X,Y,z1) -(X,Y.z2) [Vertical].

    Taking observations across frames could provide you with better results are you suspect.

    Regards,

    Kaushik