如下所示，我设置profile0，Tx0和Tx1的相位都是0,然后下面chrip使用profile0，设置chrip开始和结束都是0.
然后设置profile1,Tx0和Tx1的相位是0，180，然后下面chrip使用profile1,设置chrip开始和结束都是1，
最后frame设置为这样
这样理论上也是可以实现BPM的对吧
As shown below, I set profile0, the phases of both Tx0 and Tx1 are 0, and then the following chrip uses profile0, setting the chrip to start and end at 0.
Then set the phase of profile1, Tx0 and Tx1 to be 0, 180, then use profile1 for the following chrip, set the chrip to start and end with 1,
The final frame is set to this
This is also theoretically possible to implement BPM, right?
I use this method because when I configure BPM，
The following problem arose when visualizing the results
You can see that the top row is all phase 0, 0, 0, no inversion。By the way, when I implement BPM mode, does the position of the two antennas used matter? If I want to use three antennas to simultaneously transmit signals to achieve BPM, how can I achieve this?
thank you very much!
I have implemented the BPM mode based on the diagram below, but I'm unsure if my decoding is correct. Here is my code. Could you please help me check it, or do you have any suggestions for validation?
here is my code to decode. retVal=readDCA1000(path1); %Using the built-in readDCA1000 function to read the bin file.
%The next step is to use indexing to partition the data for translation.
n = size(retVal, 2);
blockSize = 512; %512 is my ADC sampling rate
numBlocks = n / blockSize; %Calculate the total number of blocks to be partitioned.
% Create a cell array to store the partitioned results.
Rx1 = cell(1, numBlocks/3);
Rx2 = cell(1, numBlocks/3);
Rx3 = cell(1, numBlocks/3);
for i = 1:numBlocks
startCol = (i-1) * blockSize + 1;
endCol = i * blockSize;
if rem(i,3)==1
Rx1{i}=[retVal(:, startCol:endCol)];
elseif rem(i,3)==2
Rx2{i}=[retVal(:, startCol:endCol)];
else
Rx3{i}=[retVal(:, startCol:endCol)];
end
end
Rx1 = cat(2, Rx1{:});
Rx2 = cat(2, Rx2{:});
Rx3 = cat(2, Rx3{:});
%Obtain the decoded data using addition and subtraction.
S1=(Rx1+Rx2-Rx3)/2;
S2=(Rx1-Rx2+Rx3)/2;
S3=(-Rx1+Rx2+Rx3)/2;Is it true?
在结果可视化的时候出现了下面的问题，
可以看到这个最上面一行相位都是0，0，0，没有反向。