AWR2243: format of the raw bin file collected from the cascaded 2243 radar

Dear Kaushik, can you please check where am I doing wrong.

• Number of samples = 256
• Number of Rx channels per device = 12  [3x4 for master device only]
• Number for unique chirps (in TDM MIMO example config this will be number of Tx enabled for every chirp i.e 10) : shouldnt be 3, as the data is only related to master device i.e.  "master_0000_data.bin" ?
• Number of chirp loops programmed for each of those unique chirps : 64 (number of chirps per loop?)
• Total number of frames per capture: (10)

256x12x10x64x10 = 19,660,800

I am expecting 28311552 elements. 

All the parameters are set according to "Cascade_Configuration_MIMO.lua" as I used this to capture the data. So you can take the parameters accordingly.

Hello Kaushik,

Could you kindly expedite your response to this query? Your prompt reply would be greatly appreciated.

Thank you in advance for your understanding and swift action.

Best regards

Ritesh

Thank you Kaushik for the reply. All is clear but, why sample size is taken 4? One sample is made of two elements of total 28311552 elements, one for real part and other for complex part, isn't it? So generally 28311552 elements should make 28311552/2 samples. 

when i read the bin file, there is 28311552 elements as shown in the picture, if i take one element as a real value and one element as a complex value then one sample is made of two elements. whith this logic 256x2x4x12x64x9 = 14155776 elements but we got 28311552. I am little bit confused. Please clarify. 

Hi Kaushik. So you mean When we make complex samples from the raw data as given below, it takes four elements for one complex sample? This is my data file link: https://drive.google.com/drive/folders/1IiGYaXlvlHdZwinp5295S-aLmwmhRkZ2?usp=drive_link if you need. 

Hi Kaushik. Thanks for your clarification. I got it that a complex sample is made of 4 byte and the screenshot I am showing you in previous comments, there each element is made of 8 bit. So four elements will make one complex sample. Clear!!!

However I want to understand more in detail:

clear
clc
adcIdxFileName = 'C:\ti\mmwave_studio_03_00_00_14\mmWaveStudio\PostProc\Cascade_Capture_22xx_mimo\master_0000_idx.bin';
[numIdx dataFileSize] = getValidNumFrames(adcIdxFileName); % get the number of valid frames

numSamplePerChirp=256; % The number of samples per chirp
numChirpPerLoop = 12; % The number of unique chirps per loop
numLoops = 64; % The number of loops
numRXPerDevice = 4; % The number of receive channels per chip per device
numDevices = 1; 
dataFolder = 'C:\ti\mmwave_studio_03_00_00_14\mmWaveStudio\PostProc\Cascade_Capture_22xx_mimo'; %cascade folder
fileidx = getUniqueFileIdx(dataFolder);
fileNameCascade = getBinFileNames_withIdx(dataFolder, fileidx{1,1});

read_ADC_bin_TDA2_separateFiles(fileNameCascade,1,numSamplePerChirp,numChirpPerLoop,numLoops, numRXPerDevice, numDevices);