Tool/software:
Hello TI,
According to E2E article from TI, LSB=FSR/2^N where N is the ADC resolution.
Q1: What is the LSB of ADC in xWR6843?
Q2: What is the reference voltage for the ADC in xWR6843?
From my study the threads on E2E, understand some feature of the ADC in xWR6843
- ADC Full Scale is 1V, which corresponds to 1V peak voltage at the ADC input
- ADC Full Scale is 10dBm at ADC input, because 1V peak corresponds to 10dBm power ( 50 ohms system , assuming sinusoidal signal)
- ADC resolution can be set as 12, 14 or 16-bit and default is 12-bit.
I try to calculate: If considering 12-bit ADC mode, The positive peak voltage at ADC input is 1V. The output is 0x7FF in HEX = 2047 in DEC.
Q3: Then the LSB = FSR/2^N=2/4096=0.000488V=0.488V?, or should I calculate as 2/2048 = 0.244 V?
Q4: There are "minus Full-Scale area" at the left bottom. Will there also be related code word? Does 0x000 corresponds to 0V input or -1V input?