IWR1443：The fft amplitude was converted to dbm(how 'N' is big?)

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Thank you for your answer. Pout (fft) represents the 1D-FFT amplitude of the MATLAB for "mag2db" (mag2db=20 * log10  (amplitude)). If 'N' in the second term (20log10N) represents the 1D-FFT amplitude of MATLAB, Pout (fout) and the second term cancel out, this does not seem true?

please look this articles

https://e2e.ti.com/support/sensors-group/sensors/f/sensors-forum/849044/iwr1443-how-to-calculate-range-profile-in-dbfs-or-dbm

但 Pout （ft） 表示 MATLAB 对 “mag2db” 的 1D-FFT 幅度 （mag2db=20 * log10 amplitude），这与你的答案相冲突吗？

What is the 'window' in the second item? Filter operation, noise reduction operation, FFT transformation and so on are all Windows? Please answer this example, ADC sampling point number: 128, adc-number: 16.

Performing only FFT after ADC sampling yields the following images

Is this calculation correct?   Pout(dbfs)=Pout(fft)-20log10 2^15-20log10 N-20log10√2
Finally, Pout (dbfs) =220027-20log10 2^ 15-20log10 128-20log10 √2

经过验证推导，我认为峰信息的 “220027” 代表 mv 单位，Pout （fft） =20log10 （220027）