Hi,
I have been watching TI training video about FMCW radars, and noticed angle resolution = λ/Ndcos(θ), where N is the number of receiving antenna.
So if d=λ/2 and θ=0, suggests angle resolution = 2/N, which means: 4 receiving antenna => 28deg, almost no much use in practice. if want 1deg of resolution, that needs tens even over 100 antenna!
Sounds simple math, but the results surprised me, so post here want double confirm.
Many thanks,
Zhe