Re: high accuracy lab
I understand part of the reason for multiple receive antennas so you can get angle. Why do your have multiple transmit antennas?
Per your tutorials:
S=4Ghz/40µS=100Mhz/µs=100e12
d=fc/2S=f*(3e8)/(2*100e12)=f*1.5e-6
The distance "accuracy" (i.e. <1mm) I think is 1/T where T=chirp time=40uS 1/T==25kHz
d=25e3 * 1.5e-6=.0375m=37mm which is >>1mm
Obviously, my math must be incorrect??
Thanks, Peter