Other Parts Discussed in Thread: AWR1642
Tool/software: TI-RTOS
Given the following profileCfg what is the bandwidth of the chirp?
profileCfg 0 77 7 7 58 0 0 68 1 256 5500 0 0 30
I thought that B=rampEndTime*freqSlope
where rampEndTime = 58 and freqSlope = 68
according to the rlProfileCfg_t structure from the mmWave Link doxygen: file:///C:/ti/mmwave_sdk_01_01_00_02/packages/ti/control/mmwavelink/docs/doxygen/html/structrl_profile_cfg__t.html
1LSB for rampEndTime = 10ns, therefore 58*10e-9 = 580e-9 [s]
1LSB for freqSlope = 48.279 kHz/uS, therefore 68*48.279e9= 3.283e12 [hz/s]
B=(580e-9)*(3.283e12) = 1.9e6 [hz] = 1.9MHz.
This grossly underutilizes the available bandwidth of the sensor. Am I doing something wrong with my math?