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AWR1642: IIP2 and its impact

Part Number: AWR1642

Hi champion,
  I see in AWR1642 datasheet, the in-band IIP2 is 20dBm, and the out-band IIP2 is 35dBm. Could you help to explain what is the meaning of in-band IIP2 and out-band IIP2? And what is the impact of IIP2 to system?

Thanks,
Adam

  • Hi,

    We need to check with the characterization team

    thank you
    Cesar
  • Hello Adam,

    The IIP2 is basically the point where the power of the second order IM distortion intercepts the with the power of the fundamental frequency due to nonlinearity, i.e. the 0dBc point of the second order IM distortion products.

    An in-band IIP2 is within the IF band and out-band IIP2 is outside of the IF band (in the case of the datasheet this is 10kHz). The in-band second order distortion is seen by the entire RX system including the ADC since it is withing the IF band, where as the out-band is only seen by the LNA and the mixer. So, with out-band IIP2 it is the distortion products that end up within the IF band and are seen by the ADC that we need to worry about. These tones in the frequency spectrum can show up as undesirable objects in the FFT.

    Regards,

    Adrian
  • Hello, can you give a calculation example

    for instance, there are 2 IF frequency(means 2 objects), one is 1MHZ -45dBm, another is 1.2MHZ -49dBm. then what frequency is the IM noise? and what is the power level?
  • Hello Fucai,

    The slope of the IM2 is going to be twice that of the input power. So, since the intercept point is at 20dBm for in band, we can expect the IM2 decrease twice as fast as the input from this value meaning that for an input power of -45dBm the IM2 would be equal to 2*(-45-20) = -130dBm. You can do the same for -49dBm.

    Regards,

    Adrian