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CCS/PGA411-Q1: Some confusion about EXTOUT, and how to adjust the resistance so that IEx meets the 0.5-4V range

Part Number: PGA411-Q1

Tool/software: Code Composer Studio

There are two different explanations for the output waveform of OEx, which confuse me.

Case 1:

EXTOUT is described as the minimum OEx voltage in the application manual TIDUBI2A.

Case 2:

EXTOUT adjusts the common mode voltage of OEx as found in pg 21 of DS, and my case is consistent with this one.

I calculate the OEx(min) by formula " OEx(min) = 4.25 - Vexco/4 " instead of  " OEx(min) = EXTOUT ". And my calculations are consistent with the oscilloscope tests described in my reply later.

 

  • The waveforms of OE1 and OE2 . EXTMODE = 4VRMS , EXTOUT_GL = 0xF , EXTOUT = 0x0

     

    Theoretical OExmax and OExmin were calculated using differential voltage (13.85V) and common mode voltage (4.25V).And the calculated results are consistent with the oscilloscope test results.

    OExmax = 4.25 + 13.85/4 = 7.7125V

    OExmin = 4.25 – 13.85/4 = 0.7875V

     

    The appropriate resistance value will then be calculated using formula 21.

    To make IEx greater than 0.5V,  Rmax = 40 * (0.7875 - 0.5) / 0.5 = 23KΩ

    To make IEx smaller than 4V ,  Rmin = 40 * (7.7125 - 4) / 4 = 37.125KΩ

    Because of “Rmax < Rmin”, there is no suitable R for IEx to meet the range of 0.5V-4V

     

    Is there something wrong with my OEx waveform or my calculation process ?

  • Hello, 

    Thanks for your post. 

    Please refer to the datasheet for guidance on the Exciter amplifier and its equation. You can also refer to our AFE design guide that is here