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TMS570 ARM Assembly

James Donahue
Intellectual 370 points


The following is a code snippet from a working application.

  .if $$defined(DEBUG)
 ; Change behavior of divide-by-zero.
 CP15_ENABLE_DZ_EXCEPTION R0
 .endif

I am been pouring through the ARM Assembly Language Tools v4.6 User's Guide and cannot determine why the double $, section 12.4.4 explains the $define directive, does anyone know what the second $ indicates?

Also I need to change this to be if DEBUG or DEVEL is defined but looking through the expression operators in section 3.9.1 it does not appear to support a logical OR operation.  Does someone know the correct syntax to accomplish this.

  • 0
    TI__Guru* 84285 points

    The double dollar sign has no special significance; the name of the built-in operator is '$$defined'.  For historical reasons, for ARM the dollar sign is a legal character in an assembly language identifier, and to prevent the built-in operators from being confused with potential user-defined function names, the built-in operators are named with a double dollar sign, which is different than the other TI assemblers. 

    This should work:

        .if $$defined(DEBUG) | $$defined(DEVEL)