sizeof(int) does not work

jingrui zhang

Prodigy 240 points

when I try

printf("sizeof(int)= %d\n",sizeof(int));

it gives me 0! what is this about?

over 13 years ago

0 Ki over 13 years ago

TI__Guru**** 474101 points

Hello,

Without more details, it is difficult to answer your question. The details we need are mentioned here:

http://e2e.ti.com/support/development_tools/code_composer_studio/f/81/t/3131.aspx

At minimum, the full CCS version number, compiler version number and device you are building for is needed.

Thanks

0 jingrui zhang over 13 years ago in reply to Ki

Prodigy 240 points

I am using CCS 4 with c5515.

0 Ki over 13 years ago in reply to jingrui zhang

TI__Guru**** 474101 points

Assuming you are using the latest version of v4, I tried this out with CCSv4.2.5 and using CGT version 4.3.8 and I didn't see any issue with this. I saw a value of '1', which is correct. If you are not using the latest v4 version, please update to it. If you are and still see problems, please attach a reproducible test case.

Thanks

0 Douglas Gwyn over 13 years ago in reply to Ki

Expert 2210 points

My guess is that thge call to printf was not within the scope of an #include <stdio.h>. That would change the argument passing, maybe resulting in the reported result.

0 Archaeologist over 13 years ago

TI__Guru* 84285 points

The size returned by sizeof is of type size_t, which doesn't match the format specifier %d, which is for signed int. You need to cast the result of sizeof to match the format specifier, like so:

printf("sizeof(int)= %d\n",(int)sizeof(int));

0 jingrui zhang over 13 years ago in reply to Archaeologist

Prodigy 240 points

It works. Thanks.

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sizeof(int) does not work