Converting a peripheral (space) address to an integer value?

Stephen Phillips1

I am trying to take the address of a location and cast it into a constant integer.

in particular it is an SFR address

		case	(uint16_t)&RTCSEC:

Is what I attempted first this yeilds the following error (of course)

#61 this operator is not allowed in an integral constant expression

Any suggestions as to how to get a peripheral hardware address as a constant?

I am trying to avoid doing dumb things like

	case	0x04B0://(uint16_t)RTCSEC:

Suggestions welcomed (really really welcomed)

Stephen

over 11 years ago

0 George Mock over 11 years ago

TI__Guru**** 253380 points

Your problem is that C requires case statement values to be compile time constants. You could write it like this ...

if (i == (uint16_t)&RTCSEC)

Thanks and regards,

-George

0 Stephen Phillips1 over 11 years ago in reply to George Mock

Expert 1250 points

So something like

const uint16_t rtc_sec_addr = (uint16_t)&RTCSEC;
const uint16_t rtc_day_addr = (uint16_t)&RTCDAY;

switch(address)
{
case	rtc_sec_addr:
	break;
case	rtc_day_addr:
	break;
}

might work then?

0 Stephen Phillips1 over 11 years ago in reply to Stephen Phillips1

Expert 1250 points

never mind that wouldn't work as it is not a compile time constant.
I suppose the if then clause is as good as it gets.

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Converting a peripheral (space) address to an integer value?