XDS100v2 Channel B as UART

Dmitry Cheremisin

Hi, I'm thinking to use channel B as UART and it's showing in "device manager" now as COM8. But according to wiki it is said:

"Generally, a serial port on BCBUS should connect the CPLD as follows: BCBUS1 -> CPLD TCK, BCBUS2 -> CPLD TDI, BCBUS5 -> CPLD TDO, BCBUS6 -> CPLD TMS."

But according to schematics BCBUS1, BCBUS2 are not connected and BCBUS5 and BCBUS6 are connected to CPLD. So does it mean I need to cut some traces on debugger and solder to other pins or there is possibility to remap pins?

I'm just worrying that if I will use UART like it is now I can rewrite some of the memory on CPLD.

Thanks

over 9 years ago

0 Gautam Iyer over 9 years ago

Guru 192875 points

Hi Dmitry,

Did you check this link: processors.wiki.ti.com/.../XDS100

Regards,
Gautam

0 Dmitry Cheremisin over 9 years ago in reply to Gautam Iyer

Intellectual 440 points

Hi, yes of cause, that's why I said "it's showing in "device manager" now as COM8". So this part is OK, but here processors.wiki.ti.com/.../XDS100 said:

Please note that there is a known issue with the current XDS100v2 reference design with the placement of the BCBUS. If you plan to use the port B, please check the readme of the XDS100v2 reference design for details. Generally, a serial port on BCBUS should connect the CPLD as follows: BCBUS1 -> CPLD TCK, BCBUS2 -> CPLD TDI, BCBUS5 -> CPLD TDO, BCBUS6 -> CPLD TMS.

So what to do with that? Does it mean physically cutting traces and resolder them or somehow remapping?

Thanks for reply

Code Composer Studio™︎

Code Composer Studio forum

XDS100v2 Channel B as UART