Compiler/LAUNCHXL-F28379D: Bug with stdlib.h- atof function

Okay, I will do that. Thank you for helping me out.

I don't understand you mean by ...

silsio said:

If I use "if" statement with a volatile variable, it stops at:

Please explain what you mean by "stops".  What stopped?  Exactly how do you know it stopped?  What are you looking at?

Thanks and regards,

-George

I'm sorry, but I'm still confused.  Every time you hit pause, the code is stopped in the same place?  Do you think something has gone wrong and caused an unexpected infinite loop?

Thanks and regards,

-George

Unfortunately, your description is still too vague to work with.  Please be more precise.  When the code fails, how do you know?  Exactly what do you look at?

Thanks and regards,

-George

George Mock said:

  When the code fails, how do you know? Exactly what do you look at?

I have a code which is supposed to read the output from an imu via SCI communication. The IMU sends out output as :

<-12.43>

<-12.345>

.

.

.

So, I use a code which reads this from SCI's buffer and converts into a float value when chars are between '<' and '>'. I do the char to float conversion using atof function. I have allotted a variable to this char such that it can be viewed in the "expressions" section. There was  working code which gives me the output in the "expressions" section for the variable I have allotted. This working code gives me output only when SCI buffer is read continuously in an infinity loop. I dint want to read it in an infinity loop but give control to a different function which calls it once in a while. So what this new code does is, it waits for a varialbe to go high and once it is high, it starts reading SCI buffer for a while and stops. 

However, when i run the code, it shows no output(the variable in "expressions" shows no output) and when i pause it, it always ends up at the same loop mentioned in my first comment.  When i changed the optimization level to off, I see output (the variable in "expressions" shows output) and doesnt go into any loop.

This is the best possible explanation i can give you about what's happening.

I don't understand everything in your explanation.  But I'm pretty sure you have failed to use the keyword volatile on one more more variables.  To understand volatile and when to use it, please see this article on it.

Thanks and regards,

-George

silsio said:

I use "if" statement with a volatile variable, it stops at:

#ifdef _INLINE

static __inline double atof(const char *_st)
{
  return strtod(_st, (char **)0);
}

#endif  /* _INLINE */

As I have informed before, I have used volatile keyword. 

I apologize for the delay.

silsio said:

I have allotted a variable to this char such that it can be viewed in the "expressions" section.

Consider the possibility that, due to compiler optimization, this variable no longer exists.  Try making this variable volatile.  

If that doesn't work, then I'm afraid you will have to debug the code at assembly level to work out the problem.  To understand compiler generated assembly better, add the build option --src_interlist then inspect the resulting .asm file.

Thanks and regards,

-George

I suppose you have been forced to attempt to debug this problem at assembly level.  I'm sorry about that.  Please tell us about the progress you have made.

Thanks and regards,

-George