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PMP23340C2K: PMP23340C2K Cr component selection

Alan Liu15
Intellectual 330 points

Part Number: PMP23340C2K

Hi Experts. 

I'm studying the PMP23340C2K LLC Converter. 

About the Cr component selection and design.  From my understanding, the Cr total is 3.52uF.

The reason to use 16 MLCC's to parallel to meet the require capacitance is to meet the rms current. 

Am I correct ?

And w/ my design, if I wanna change it to 6V/1.1KW, the Cr calculated is 0.6uF, Fr = 1MHz, I use 0.056uF * 11PCS to parallel and each's ripple current is 3.5A@1MHz.

The Ipri,rms is around 28A. Use 11~12 pcs to meet the Cr capacitance and current should be ok, right ?

Thanks. 

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