CC2640R2F: problems with bootloader

Do you connect IOID_12 with GND to enter boot loader?

Yes, I connected, but it seems that he does not enter the bootloader

How do you know it doesn't enter bootloader? Try to refer to steps in sunmaysky.blogspot.tw/.../how-to-use-backdoor-serial-boot-loader.html

How do I know that we go into bootloader mode?

You can refer to section 2.3.3 Establishing Communication in www.ti.com/.../swra466a.pdf

With a clean chip, everything works for me. I want to use the project with Github.

I couldn't understand your question. Can you elaborate?

I flash the chip, go to the SmartRF Flash programmer 2, select the correct chip from the virtual COM port, put the jumper between the DIO12 and GND outputs, press RESET on the board, then press the right mouse button to connect the chip from the virtual COM port, and the SmartRF Flash programmer 2 gives an error.

What error do you see?

>Initiate access to target: COM5.
>No response from device. Device may not be in bootloader mode. Reset device and try again.
If problem persists, check connection and baud rate.
>Connecting over serial bootloader failed: No response from device. Device may not be in bootloader mode. Reset device and try again.
If problem persists, check connection and baud rate.
>Failed to create device object.

Try to do a mass erase from flash programmer 2 and test again.

Again, with a clean chip, I have no problems, it immediately enters the bootloader mode. I'm using the project with Github (github.com/.../serial_bootloader.md), and when I flash it on the chip, and follow the instructions, there are problems about which I above already mentioned.

Do you either exclude ccfg.c from the build, or don't tell the linker to place the CCFG section?

In the project I want to flash through UART, I exclude ccfg.c from the assembly. Or should ccfg.c be excluded from the Serial Boat Loader project?

Thanks a lot, it solved my problem.

Can I enter the bootloader without closing the contacts? Or is it already hardware embedded in the chip?

I couldn't understand your question. Can you elaborate?