• State Resolved
  • Locked Locked
  • Replies 3 replies
  • Subscribers 56 subscribers
  • Views 581 views
  • Users 0 members are here
Support feedback
Options
Options
Related

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

Command for direct joining

Prasoon Sharma
Prodigy 75 points

Hello all,

I'm using Z-Tool for setting up a Zigbee network. I want to know that if there exists any command in Z-Tool that can send a direct join request to a device(not already a part of the network) from my coordinator such that I do not need to do anything on the device that needs to be joined(no button press or anything).

So far I've used ZDO_MGMT_DIRECT_JOIN_REQ for doing so. With this command the device that needs to be joined gets assigned a short address and also comes in the association list of my coordinator but still I could not control it by sending commands. I still need to press the button from the device to be joined. It(device to be joined) then sends ZDO_END_DEVICE_ANNCE_IND and only after that I could control the device.

Regards
Prasoon

  • +1
    Guru 735705 points

    There’s no such MT command for this.

  • +1
    TI__Guru**** 224177 points

    Hello Prasoon,

    Although the ZC has stored information about the joining device, this device still needs to complete the join process so that it can associate with the network, receive the network key (most important since messages are encrypted), and announce its presence on the network.  If you do not want the user to interact with the device in order for it to join, the joining device could be set up to continuously attempt commissioning until it finds a network to associate with.   The risk here is whether there are any nearby and open Zigbee networks within the same channel which the device could unintentionally join.

    Regards,
    Ryan 

  • 0 in reply to Ryan Brown1
    Prodigy 75 points

    Thanks Ryan and YK for the answer.