CC2530: how HAL_ISR_FUNCTION work ?

navidrct ansari

Expert 1975 points

Part Number: CC2530

I want the port1 of cc2530 has interrupt

now I write to these register to have interrupt

  P1SEL &=  ~(1<<5); //set it to use GPIO
  P1IEN |= (1<<5); // interupt enable
  PICTL |= (1<<2); // interupt on falling edge
  P1IFG = 0x00; // clear interupt flag

and write this function

HAL_ISR_FUNCTION(halKeyPort1Isr , P1INT_VECTOR ){

P1IFG = 0x00;

}

I think function above is not right because it's not triggering

everything else is right and I test it

over 8 years ago

0 YiKai Chen over 8 years ago

Guru 735695 points

You miss “P1DIR &= ~(1<<5);”

0 navidrct ansari over 8 years ago in reply to YiKai Chen

Expert 1975 points

direction as default is zero so it won't be needed

how can I write my interrupt function to be hitten whenever its happen?

0 YiKai Chen over 8 years ago in reply to navidrct ansari

Guru 735695 points

You also miss IEN2 setting.

0 navidrct ansari over 8 years ago in reply to YiKai Chen

Expert 1975 points

thanks i change it but not working

  P1SEL &=  ~(1<<5); //set it to use GPIO
  P1IEN |= (1<<5); // interupt enable
  PICTL |= (1<<2); // interupt on falling edge
  P1IFG = 0x00; // clear interupt flag
  IEN2 |= (1<<1);
  HAL_ENABLE_INTERRUPTS();

0 navidrct ansari over 8 years ago in reply to navidrct ansari

Expert 1975 points

i did it

this is how u should do it

  P1SEL &=  ~(1<<5); //set it to use GPIO
  P1DIR &= ~(1<<5);
  P1IEN |= (1<<5); // interupt enable
  PICTL |= (1<<2); // interupt on falling edge
  IEN2 |= (1<<4); //Port 1 interrupt enable
  IEN0 |= 0x80;     // enable global interrupt (EA)
  P1IFG = 0x00; // clear interupt flag
  P1IF = 0x00;

and for interupt function

int i = 0 ;
HAL_ISR_FUNCTION(halKeyPort1Isr , P1INT_VECTOR ){

  HAL_ENTER_ISR();
  i++;
  P1IFG &= ~(1 << 5);
  IRCON2 &= ~(1 << 3);
  
  printf("interupt %d \r\n" , i);

  HAL_EXIT_ISR();

}

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CC2530: how HAL_ISR_FUNCTION work ?