CC2630: Question for IEEE 802.15.4 MAC Address Rule (CC2630/CC2650)

in kook jang17

Intellectual 380 points

Part Number: CC2630

Hi Experts,

I checked the IEEE 802.15.4 Mac Address as shown below. (00:12:4B:00:0F:28:C7:05)

It is confirmed that the address is purchased by TI. (refer to below)

I know that I use EUI-48 addresses to generate EUI-64 addresses.

The actual MAC address is read as follows. (00: 12: 4B: 00: 0F: 28: C7: 05)

1. What does mean in the address Value(00: 0F)?

2.Is it a product identification number?

3. Is it a value generated by applying its own calculation method?

4. Is it simply a number from 0000 to FFFF?

Thank you for your help.

Br, IK

over 6 years ago

0 Ryan Brown1 over 6 years ago

TI__Guru**** 217467 points

Hi IK,

The two bytes in question are not completely random, calculated, or unique per device as far as I can tell. I'll try to find an expert at TI who knows more about this value but meanwhile I do not recommend making any assumptions or interpretations from it inside your application.

Regards,
Ryan

0 in kook jang17 over 6 years ago in reply to Ryan Brown1

Intellectual 380 points

Dear Ryan.

Thank you for your kind reply.

Do you have any update?

Br, IK

0 Ryan Brown1 over 6 years ago in reply to in kook jang17

TI__Guru**** 217467 points

The response to your questions is as follows:

1. No significance other than being part of the 40-bit unique device identifier part of the 64-bit address range
2. No
3. No
4. Yes

The 64 MAC address range is the entire 40 bit range for the 00:12:4B block, TI does not generate 64-bit addresses from a 48-bit MAC.

Regards,
Ryan

0 in kook jang17 over 6 years ago in reply to Ryan Brown1

Intellectual 380 points

Dear Ryan,

Thank you for your Kind & Detail Reply.

It's very clear & helped to me.

Thank you.

Br, IK

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CC2630: Question for IEEE 802.15.4 MAC Address Rule (CC2630/CC2650)