EMIF in C6678

shuailin wang

Prodigy 20 points

Hi,

I am in trouble when I change the register Async 2.

When I change Async 2 from 0x3FFFFFFD to 0x3FFFFFFC,there is no change in data bus which should be 8-bit data bus.

What should I do to set the data bus to 8-bit?

The following picture is captured from FPGA's SignalTap

Thanks,

Shuailin

over 12 years ago

0 RandyP over 12 years ago

TI__Guru* 84110 points

What address are you writing to and what is the code you use to write the data?

0 Aditya over 12 years ago

TI__Expert 6815 points

Shuailin,

Can you confirm that you are configuring the Async register for the correct CE space?

Async1 config corresponds to CE0 space: 0x70000000 - 0x73FFFFFF

Async2 config corresponds to CE1 space: 0x74000000 - 0x77FFFFFF

Async3 config corresponds to CE2 space: 0x78000000 - 0x7BFFFFFF

Async4 config corresponds to CE3 space: 0x7C000000 - 0x7FFFFFFF

0 shuailin wang over 12 years ago in reply to RandyP

Prodigy 20 points

My code is:

regs->A2CR = (regs->A2CR & 0x00000000) | 0x3FFFFFFD;

for(i=0;i<=15;i++)

{ *(volatile *) (0x74000000+0x4*i) = (uint32_t)(i+1);}

thanks,

shuailin

0 RandyP over 12 years ago in reply to shuailin wang

TI__Guru* 84110 points

For the code you have shown, the display in your original post appears to be correct operation.

I am not sure why you wrote it the way you did. Does the optimizer get rid of the (read & 0)? If not, I would remove that unless you have some reason for it.

Regards,
RandyP

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EMIF in C6678