Part Number: LM339A Other Parts Discussed in Thread: TLC374 Hi TI Experts
When I use LM339APWR ,12V VCC, and the positive Input 5V as reference voltage, and how to make sure the propagation delay time? use the max 1.3us as the worst case propagation…
Part Number: LM339A Other Parts Discussed in Thread: TLV1704 , TLV7044 , TLV9024 , TLV3404 , LM339LV , LM339 Hi TI Experts
LM339APWR VCC:5V ,Positive IN=Reference Voltage=4.5V as below shows.
When the Negative IN rise to about 4.369V then will be…
Part Number: LM339A Other Parts Discussed in Thread: LM339-N , TL331 , LM397 , LM393 Hello,
I has to use two of four comparators of a LM339AM in a safety function.
How are the internal circuits an components connectet and there are more components…
Part Number: LM339A Other Parts Discussed in Thread: LM339 Hi,
Could you please tell me the difference between LM339ANSR and LM339NSR? I can NOT find the answer from the datasheet.
Thanks.
Kevin Xiong
Part Number: LM339A Dear Team,
My schematic is as below figure.
From the scope, we saw there is about 300 ms response time between Vout and Vin.
If we change R5265 to 3.24K, Vin will be lower, and we can see the response time is only 200us.…
Part Number: LM339A Hi,
we use LM339A as comparator under +/- power supply. there are two situations we need to confirm.
(1) V+ = +5.3V and V- = -5.3V
(2) V+ = +18.5V and V- = -5.3V
Coudl work noramlly under these power supply? If it can, what…
Other Parts Discussed in Thread: LM339A , LM339 Hi
I'm planning to build design based on the LM339A OPA. I've tried to use its Pspice model from TI library and found it is not working (for me). tried also very simple circuit (see attached) and got unreasonable…
Other Parts Discussed in Thread: LM339A Hi Team,
Could you please tell me in detail about the test condition of LM339A , in the table below ?
[Q1] Could you give me an explanation in specific what "5mV overdrive" mean ?
[Q2] The condition for…
Part Number: LM27761EVM Other Parts Discussed in Thread: LM27761 , LM339A According to the data sheet, the formula for Vout is -1.22*(R1+R2)/R2
where Vfb should be (1.22) between 1.202V and 1.238V
So I choose R1=115K and R2=499K to get Vout=-1.5V…
