Part Number: LMV339 Hello,
Please confirm lifecycle of item LMV339IPWR. is this part active for 5-7 Years or not?
Is there any plan to discontinue this item? if yes then please provide alternate part details.
Part Number: LMV339 Other Parts Discussed in Thread: LM393LV , LM339LV Hello,
we use 13x LMV339 to detect over current in our circuit but have overlooked that it does not support rail to rail input operation. The input needs to stay 700mV below supply…
Part Number: LMV339 Hi All,
I have a question regarding the power supply of the LMV339 comparator to be used on a new customer project.
The questions are: • Is it good to power the LMV339 at + 5V? • if so what margin do we have? • why in the absolute…
Part Number: LMV339 Hi, I am confused for LMV339 differences in cost for individual marking. For example LMV339M/NOPB costs about 1usd. But for example LMV339IDR costs about 0,3usd. It is three times lower price for the same device. What is the reason…
Part Number: LMV339 Other Parts Discussed in Thread: LMV393 Hi team,
My customer is designing the schematic with LMV339. The customer would like to know the propagation delay time.
Could you please give your advice for below question?
Figure 5 and 6…
Part Number: LMV339IDR We are using the LMV339 oparating at 5.0V.
The datasheet 7.6 Electrical Characteristics describes the common mode input voltage as 25 ° C -0.1 to 4.2 V, but the chapter 9.2.2.1 Input Voltage Range describes as follows.
"If…
Part Number: LMV339 Other Parts Discussed in Thread: LMV331 , TLV7032 , TLV7042 VICR Common-mode input voltage range is only specified at 25°C
What is the performance for VICR Common-mode input over full operating temperature
Part Number: LMV339 Hi team.
Could you give me some advice how to handle unused terminals?
I'm happy to tell me the recommended resistance value.
Sincerely.
Kengo.
Part Number: LMV339 Hi team.
I am confusing about absolute maximum ratings.
I'd like to give me your advice in below things.
1. The minimum of VICR(-0.1V) exceeds the absolute maximum rating(VI=0V).
Why is this?
2. If it is mistake , will you change…