Part Number: OPA177 Tool/software: Hello there,
can somebody help me to find where can I fill the samples program request form?
Unfortunately link in the page https://www.ti.com/ordering-resources/faqs/inventory-product-availability/sample-request.htm…
Part Number: OPA177 Other Parts Discussed in Thread: OPA191 , OPA192 , OPA206 , OPA196
Tool/software:
Hi Team,
Do we have rail-to-rail output performance device that can Pin2Pin replace OPA177? Customer need this spec to meet system requirement. Thanks…
Part Number: OPA177 Other Parts Discussed in Thread: OPA192 , Hi.
I need to increase the value measured by a sensor giving 0-30mV output by 100 times and process it with an MCU.
I built the circuit below. However, when I connect the sensor to the input…
Part Number: OPA177 Other Parts Discussed in Thread: TINA-TI , OPA192 , OPA197 HI Team,
We need to have 0 to 10.2V DACOUT swing. 0 to 3V is the DAC input to opamp. With OPA177 part, the output is 0.874V with 0V input to non-inverting amplifier.
But the device…
Part Number: OPA177 Other Parts Discussed in Thread: OPA197 Hi Team,
Does OPA177GS support single supply? What is the range?
Kindly revert.
Thanks,
Vidhya
Hi Jack
Jack Terrell said: The OPA277U is probably the best alternative, but it's expensive and has been out for 25 years (so maybe not for much lon Jack Terrell said: Will it come out anytime soon, or do you have any other ideas on what to use instead…
Part Number: OPA177
Hello All,
I'm trying to use the OPA177GS as a peak detector, as shown in the circuit.
My issue is that, theoretically the output should be able to maintain the peak voltage.
Does the op-amp has somekind of internall resistance…
Part Number: OPA177 Other Parts Discussed in Thread: OPA191 Hello:
I’m considering using the Texas Instruments (Burr-Brown) OPA177 for some simple precision inverting operational amplifier designs. The applications will be a differential amplifier, inverting…
Hi Bastian,
a 100mH coil has a impedance of 2 x pi x 80Hz x 100mH = 50R. A sine voltage swing of 15Vpp or 7.5Vp would cause a current of 7.5Vp / 50R = 150mAp. This is much more than your given 18mA.
Is my calculation correct?
Kai