Tool/software:
Hello experts,
I plan to use TL082CPS as a comparator.
[Supply voltage]
VCC=+12+5%
VEE=-12-5%
[Question]
- What is the voltage (min/max) on the positive and negative sides of the output in this situation?
I read datasheet "6.12 Electrical Characteristics", it shows (min)Vom=±12V,(typ) ±13.5V ,at Vcc=±15V, 25℃. So I want to know the situation at Vcc=±12V(±5%), 25℃.
Best regards,
Hiromu