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OPA376: OPA376

Hironari Ishiguro
Prodigy 130 points
Part Number: OPA376

Tool/software:

Regarding OPA376 using a differential amplifiren(gain 2) with 5V power supply, if the power was changed like a few % by temp or something, should the output consider to change by changing the power?  

I don't see any data on your data sheet. I appreciarte if you could answer how change the output by changing the power?

Thank you  and BEST REGARDS,

Hironari

  • 0
    TI__Mastermind 25990 points

    Ishiguro-san

    I believe the parameter you are seeking is PSRR (power supply rejection ratio) which specifies how much input offset voltage changes for changes in the power supply.

    Chuck

  • 0 in reply to Chuck Sins
    Prodigy 130 points

    Thank you very much your quick reply. So, there is a table showing  PSRR that is 5uV/V @ 25degC and 5uV/V @ temp. So, if the power changed 10%, both would be changed 10% of 5uV respectively.  Then the output would be changed according to the gain ( x 2). So, the total shift by chnageing the power at the output can be caliculated as [ (5uV/V x 5V(power) x 10% (@25degC) + 5uv/V x 5V(power) x 10%) x 2] =    2.5 +2.5 = 5uV. Is it correct?

  • 0 in reply to Hironari Ishiguro
    TI__Guru**** 165326 points

    Ishiguro-san,

    10% of 5V is 0.5V, 0.5V * 5uV/V = 2.5uV input referred Vos change.

    Diff amp signal gain of 2 puts op amp in loop gain (also called noise gain) of 3. 2.5uV *3 = 7.5uV typical change at output.