Other Parts Discussed in Thread: TCAN4550, TCAN4550EVM
Hi Team,
My customer is going to artwork the CAN bus line on the PCB with a differential impedance 120 ohm line.
Since it is a 120 ohm line, it will be quite thin, but what is the current flowing through the CAN line?
I think it is the following calculation when DOMINANT.
(CANH - CANL)/R = (3.5 - 1.5)/120 = 16.7mA
Is it correct?
Best Regards,
Kenji


