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Original question:

ADS1292: Data converters forum

ADS1292: How to turn off the current source in DC lead-off mode?

user6486525
Prodigy 70 points
Part Number: ADS1292
Other Parts Discussed in Thread: ADS1294

In the 8.3.10.2.1 DC Lead-Off mode of the ADS1292 Datasheet, two modes are provided: a) External Pull-Up/Pull-Down Resistors and b) Input Current Source. We now want to choose the a) method, but we don’t know how to turn off the b) Input Current Source.

In the 8.6.1.4 LOFF register configuration in this datasheet, Bit 4 must be set to ‘1’ according to the description. However, the description of this register in devices of the same type, such as the ADS1294, clearly states that bit4 is the option of VLEAD_OFF_EN, 0 = Current source mode lead-off, 1 = pullup or pulldown resistor mode lead-off.

So, what I urgently want to know is, regarding the description in this section of 8.3.10.2.1 DC Lead-Off, is there only the a) External Pull-Up/Pull-Down Resistors option, but no b) Input Current Source option?

  • 0
    Prodigy 70 points

    Could you provide me with some guidance or validation? I’m currently using method a) in my circuit. However, I’ve noticed that altering the value of Bits[3:2] in the LOFF register, specifically ILEAD_OFF[1:0], influences the read value of LOFF_STAT. This observation leads me to believe that method b) is also operational at this moment.