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When the ADS1015 is powered at Vcc = 3.3V, and the mux is configured so the AIN0 switch is open. What will the leakage current be into AIN0 when AIN0 = 3V? Thx!
When the ADS1015 is powered, can I open the MUX switches such that AIN0 is isolated from the part’s AFE? If so, what is the leakage current at 3.0V input? VDD would be at 3.3V.