I have a PCA9306 wired up as it shows in Figure 6 of the datasheet (normal setup), however, Vcc1 is 2.8V and Vcc2 is 3.3V. I’m trying to figure out what the current is across the bias resistor (using the formulas in figure 13), but this doesn’t work out since Vcc2 < Vcc1 + Vth (or maybe it does and the current is reverse).
In this mode of operation, which is similar to what is described in section 8.1.5, is there a method to calculate bias current, or is it effectively zero and/or just the leakage current of the device?
