DS90UB948-Q1: questions about 0x49 of 948

Betty Guo

Expert 7300 points

Part Number: DS90UB948-Q1

Hi team,

what's the status of bit[5] of reg 0x49 of DS90UB948 if bit[6]=1?

I found that if set bit[6]=1, some time the bit[5] is 1, sometimes is 0.

thank you

over 4 years ago

0 Hamzeh Jaradat over 4 years ago

TI__Guru** 107910 points

Hello Betty,

Reg 0x49[6] is the MAPSEL Over Write enable from register configuration, and bit [5] is the Register setting of MAPSEL mode if MAPSEL OVER WRITE is set.

This means, if you write bit[6]=1, you enable over writing the MAPSEL in bit[5]. So you can write any value in [5]

0 Betty Guo over 4 years ago in reply to Hamzeh Jaradat

TI__Expert 7300 points

hello Hamzeh,

what's the difference between bit[5]=1 and bit[5]=0?

0 Hamzeh Jaradat over 4 years ago in reply to Betty Guo

TI__Guru** 107910 points

This bit is the MAPSEL status, if MAPSEL High or Low. See datasheet.

0 Betty Guo over 4 years ago in reply to Hamzeh Jaradat

TI__Expert 7300 points

Hi Hamzeh,

OK.

actually, we care about is that why the 0x49 will be change during normal work?

in init 948, we write 0x49=0x60

during normal work, read 0x49 value, will read different value sometimes. what will cause 0x49 change without software and hardware change?

thank you

0 Hamzeh Jaradat over 4 years ago in reply to Betty Guo

TI__Guru** 107910 points

Hello Betty,

If you enable the Over write bit, then bit [5] should not change during normal operation!

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DS90UB948-Q1: questions about 0x49 of 948