Hi Team,
The datasheet shows the following however 0x6F[7] shows a "RESERVED" bit.
Is the following 0x6F[7] typo?
Best Regards,
Yaita
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Hi Team,
The datasheet shows the following however 0x6F[7] shows a "RESERVED" bit.
Is the following 0x6F[7] typo?
Best Regards,
Yaita
Hello Yaita,
Yes, this is a typo. Register 0x2F[0] starts the adaptation.
Regards,
Kia Rahbar
HiYaita-san,
Correction: the datasheet statement about 0x6F[7] is correct, though the description for this reserved bit is not included. See description below:
Address (Hex) |
Bits |
Default Value (Hex) |
Mode |
EEPROM |
Field Name |
Description |
6F |
7 |
0 |
RW |
Y |
EN_LOW_DIVSEL_EQ |
1: EQ adaption will be performed for all divider settings 0: EQ adaption will only be performed for dividers of 1 and 2 |
6:5 |
0 |
RW |
Y |
RESERVED |
|
|
4:0 |
0 |
RW |
N |
RESERVED |
|
Regards,
Rodrigo Natal