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AM26C31: Why does pin G need to be GND?

Part Number: AM26C31

Hi team,

I had a customer that wants to design in AM26C31 and had some questions.

About the reference design as the datasheet, why pin G needs to connect to GND? It can't meet the true table.

  • Hi Len,

    The table shows that the device has high-impedance outputs only when G is low and  is high. In the example you provided, tying G low allows the user to use G̅ as a negative-logic input (active low enable). Another implementation would be to tie G̅ high. This would allow G to be used as an positive-logic input (active high enable).

    The first figure you included is just a common/typical application. It is not the only way to implement the G/G̅ enables.

    Keep in mind that, although "X" in the Function Table indicates that the state of the input is irrelevant, it is ill-advised to leave an unused input pin floating on a device. This is why the image you referenced shows the unused input tied to GND.

    Best,

    Danny