DS125BR111: Can EQA1 and EQA2 be connected directly to GND instead of pulling down to GND with a 1k resistor？

Junior Li

Part Number: DS125BR111

Can EQA1 and EQA2 be connected directly to GND instead of pulling down to GND with a 1k resistor（shown in DS 8.3）？What is the influence on overall functionality ?

over 3 years ago

0 Drew Miller1 over 3 years ago

TI__Mastermind 37143 points

Hi,

It is recommended to use 1k resistors in order to limit the startup current of the integrated 2.5V regulator. From a logic perspective, pulling down to GND vs 1k to GND is the same, but pulling down directly to GND may impact device startup.

Thanks,

Drew

0 Junior Li over 3 years ago in reply to Drew Miller1

TI__Prodigy 80 points

If we don't use the integrated 2.5V ,tie it to GND ,is there any risk?

0 Drew Miller1 over 3 years ago in reply to Junior Li

TI__Mastermind 37143 points

Hi,

Based on the logic thresholds that are shown in the datasheet, this should work. However, this is not something that we have verified, so we cannot guarantee that it will work.

Thanks,

Drew

0 Junior Li over 3 years ago in reply to Drew Miller1

TI__Prodigy 80 points

Hi ,If the 1K resistor is just to limit the current ,when we decide not to use the integrated 2.5V ,can we tie the pin to GND without a resistor? What is the risk?May the integrated 2.5V is used for internal power supply?

0 Drew Miller1 over 3 years ago in reply to Junior Li

TI__Mastermind 37143 points

Hi,

Based on my understanding of the device, it should work fine to tie the pin to GND when you are not using the integrated 2.5V supply. With that said, validation for this device was done using 1K to GND. Because of this, it is possible that connecting the pin directly to GND may result in unexpected behavior since this use case has not been validated. Since the part has not been validated under this use case, we cannot guarantee that it will work.

Thanks,

Drew

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DS125BR111: Can EQA1 and EQA2 be connected directly to GND instead of pulling down to GND with a 1k resistor？