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Hi Team, seeking some help.
The load resistors are set so IOH/IOL doesn't exceed +/-1mA at maximum output voltages. The key is CC compensation capacitor. Ideally R1 x CC = R2 x Cin. since 20pF is the maximum RTG4 MSIOD input capacitance, I scaled the ratio for Cin = 15pF. The value of CC needs to be verified by test in the lab. It is the only "critical" selection for optimal waveform profile. I used 1% resistors, but they could easily be 5%. the clock will be 40MHz, the worst case we need is 80MHz.
ELECTRICAL CHARACTERISTICS page 5 see below, VOHmin (@IOH = -4mA) = 2.4V and VOLmin (@IOL = 4mA) = 0.4V. this is the right parameters for the worst case analysis
or I need to use figure 7 & 8 for the worst case analysis. for example, i need the output to be 2.5V from the figure the output current should be around 16mA. can you please confirm if i need to use +/-4mA or 16mA for worst case analysis. see below
FPGA input Level see below...
below we add voltage divider between your IC and FPGA. "voltage level shifter" I need to make sure my solution dose not affect your IC on worst case analysis.
Hoping for your kind assistance.
Thank you.
-Mark
Mark
Please let me take a look at this question and get back to you tomorrow.
Thanks
David
Regardless of their DC ratings, logic outputs are designed to drive small capacitive loads like CMOS inputs. In general, anything up to 70 pF is OK.
A simpler but more expensive alternative would be to shift the voltage down with a buffer with an overvoltage-tolerant input, e.g., SN74LVC1G34 or SN74AUP1G34.
Mark
I would go with the value in the table as the worst case analysis.
Thanks
David
Hi David,
For example we need 2.5 output you need 4 mA max (datasheet). but if you look at the 2 graph in the data sheet for the output voltage and the output current in our case you need 2.5 volt output and the output 13mA around.
Hi Mark,
I believe the EC table would be more accurate for worst case analysis. The EC table spec is saying that a VOH minimum of 2.4V can is expected with a IOH of 4 mA.